Question

16. The following figure shows a square ABCD and an equilateral triangle DCE. Prove that





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Answer 1

Answer:

WHERE IS THE FIGURE??

Step-by-step explanation:

Answer 2

Step-by-step explanation:

∠ADC=∠BCD=90∘→square∠CDE=∠DCE=60∘→equilateral_triangle∴∠ADE=∠BCE=150∘InΔADEandΔBCEAD=BCDE=CE∠ADE=∠BCEΔADE≅ΔBCE