Question

16) The force of attraction between two bodies at a certain separation is 100N.
What will be the force of attraction between them if the separation is reduced to
half?​

Answer 1

The force of attraction is inversly proportional to the square of the distance between the objects. So if the distance of separation is reduced to half then the force will get quadrapuled. So the force between the objects is 40N now.

Answer 2

AnswEr :

We're given that a force of attraction between two bodies at a certain separation is 100N.

And we've to find the force of attraction between them if the separation is reduced to half.

We know that the area force is attraction between 2 objects is given as :

➝ F = 100 N

➝ F = G × (m1 × m2)/r² ⠀⠀⠀⠀eqn (1).

where,

• G is the Gravitational constant

• F is gravitational force /pull

• m1 & m2 are the masses of the respective bodies.

• r is the distance.

According to the question, if distance between the object is reduced to half. So as per the above eqn of force, it would become exactly it's four times.

That is,

⇒ F = G × (m1 × m2)/r²/4

Solving further,

⇒ F' = 4 × F [From eqn 1]

⇒ F' = 4 × 100

⇒ F' = 400 N [Newly obtained force]

∴ Force of attraction between them if theseparation is reduced to half is 400 N.