Question

(16) The length of a diagonal of quadrilateral 121 m and the length of the
perpendiculars drawn from the remaining vertices to this diagonal are 40m
and 80 m respectively. Find the area of the quadrilateral.​

Answer 1

Answer:

Step-by-step explanation

Consider ABCD to be the quadrilateral.

Drawing a diagonal will convert the quadrilateral tp 2 triangles.

Now Area of Quadrilateral = Area of Both triangles

= ( 1/2 * b * h ) + ( 1/2 * b * h )

= (1/2 * 121 * 40 ) + ( 1/2 * 121 * 80 )

= (121 * 20 ) + ( 121 * 40)

= 2420 + 4840

= 7260 m²

Answer 2

Answer:

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Step-by-step explanation:

in first case ,

base,b=121 m

height, h=40 m

Now,

area of triangle =1/2×121×40

=2420 m²

in second case ,

base. b =121 m

height, h= 80 m

area of triangle= 1/2×121×80

= 4840 m²

therefore sum of the two Triangle = 2420 m² + 4840m²

= 7260m²