Question

16. The length of a rectangle is 5 m greater than its width. If the perimeter of the rectangle is 50m find its length​

Answer 1

Answer

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Given,

• the length of a rectangle is 5 metre greater than its width .
• the perimeter of the rectangle is 50

To find,

• its length

Now,

Let the length = x+5

and we know that the breath is "x" .

Then ,

$\bold{x + x + 5 = 50}$

$= > 2x + 5 = 50$

$= > 2x = 50 - 5$

$= > x = \frac{45}{2}$

$= > x = 22.5$

The width of the rectangle is 22.5 cm .

the length =(X+5)= 22.5+5 = 23.0 = 23cm .

The length is 23cm .

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Answer 2

GIVEN:-

The length of a rectangle is 5 m greater than its width.

Perimeter of the rectangle is 50m.

To Find:-

Find its length.

SOLUTION:-

Let the width be x and length be

x + 5.

Perimeter = 50 m.

Formula of perimeter of rectangle,

$\boxed{\sf{2(length+breadth) }}$

According to the question,

$\large\Longrightarrow{\sf{Perimeter=2(length+breadth) }}$

$\large\Longrightarrow{\sf{50=2(x+x+5) }}$

$\large\Longrightarrow{\sf{50=2(2x+5) }}$

$\large\Longrightarrow{\sf{50=4x+10}}$

$\large\Longrightarrow{\sf{50-10=4x }}$

$\large\Longrightarrow{\sf{40=4x }}$

$\large\Longrightarrow{\sf{\huge\frac{40}{4}\large\:=x}}$

$\large\Longrightarrow{\sf{10=x }}$

$\large\therefore\boxed{\sf{x=10}}$

Therefore,

The width is 10 m.

Length = x + 5 = 10 + 5 = 15 m.

$\large\green\therefore\boxed{\sf{\green{Length \:of \:the \:rectangle\: is\: 15\: m. }}}$