Question

16. The length of a rectangle is 6 metres more than its breadth. The perimeter of the rectangle is 60 metres. Find the length and breadth of the rectangle.

please answer me correctly.​

Answer 1

Given:

The length of the rectangle is 6 metres more than its breadth.

Perimeter of rectangle = 60m

To find:

Length and breadth of the rectangle

Solution:

Let the breadth of the rectangle be x metres.

Let the length of the rectangle be (x+6) metres.

As we know that,

Perimeter of rectangle = 2(l+b)

So,

60 = 2{(x+6)+x}

60 = 2{x+6+x}

60 = 2{2x+6}

60 = 4x+12

60-12 = 4x

48 = 4x

$\frac{48}{4} = x$

$\bf \pink{12 = x}$

Verification:

On substituting the value of x as 12 in the equation,

60 = 2{(12+6)+12}

60 = 2{18+12}

60 = 2×30

60 = 60

LHS = RHS

Hence Verified!

Now,

Breadth = x

= 12m

Length = x+6

= 12+6

= 18m

Final answer:

The length of the rectangle is 18m and the breadth of the rectangle is 12m.

Answer 2

Answer:

Given :

The length of a rectangle is 6 metres more than its breadth.

The perimeter of the rectangle is 60 metres.

The length of the rectangle is 6m > breadth.

Perimeter of rectangle = 60 m.

Now, let's assume length as x and breadth as y

Length = 6 + y

The formula for perimeter of a rectangle is

2 ( x + y ) or 2x + 2y in simpler words.

Now, according to this formula,

60 = 2 ( x + 6 + × )( We will find y later )

= 60 = 2x + 12 + 2x

= 72 = 4x

= x = 72/4

= x = 18

So the value of x is 18

Therefore, the value of y = x - 6

= 18 - 6

= 12 cm

Now, let's have a final check.

Perimeter of rectangle

= 2x + 2y

= 2 * 18 + 2 * 12

= 36 + 24

= 60.