16. The ratio of ages of two persons is 7: 11. Seven years hence, the ratio of their ages will be 2:3
Find their present ages.
Answers
Answer:-
Let's take a common factor between the ratios
Let's take a common factor between the ratiosLet the common factor be
So, the present ages of the two persons are and respectively.
After 7 years there ages will be
Therefore according to the question the equation formed is
∴ Present age of one person = 7x
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 7 × 7
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 49
Present age of another person = 11x
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀ = 11 × 7
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 77
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Given :
- The ratio of ages of two persons is 7 : 11
- Seven years hence, the ratio of their ages will be 2 : 3
To Find :
- Their present ages
Solution :
Let, the common factor be 'x'
Given that,
- The ratio of ages of two persons is 7 : 11
So, the present ages of the two persons are '7x' and '11x' respectively
☆ After 7 years,
Their ages will be '7x + 5' and '11x + 5'
A.T.Q :
⇒ (7x + 5)/(11x + 5) = 2/3
⇒ 3(7x + 5) = 2(11x + 5)
⇒ 21x + 15 = 22x + 10
⇒ 21x - 22x = 10 - 15
⇒ - x = - 5
⇒ x = 5
∴ Present age of 1st person = 7x
= 7 × 5
= 35 year
∴ Present age of 2nd person = 11x
= 11 × 5
= 55 year
Verification :
We have,
⇒ (7x + 5)/(11x + 5) = 2/3
Substituting the value of x,
⇒ {7(5) + 5}/{11(5) + 5} = 2/3
⇒ (35 + 5)/(55 +5) = 2/3
⇒ (40)/60 = 2/3
⇒ 2/3 = 2/3