16. The recoil velocity of pistol is 1.5 m.s-1.The velocity of bullet of mass 5
gram which is fired from a pistol of mass 1.5 kg is :*
- 450 m/s
O + 450 m/s
O .45 m/s
+45 m/s
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Answer:
if i use conservation of momentum over there
m1u1 = m2v2
mv = p
so The velocity of the bullet (V) = mass of pistolx velocity of pistol / mass of bullet.or, V= 1.5 x 1.5 / 0.005.or, V = 2.25 / 0.005.or, V = 450 m / second.
Hope it will help you
Explanation:
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