Question

16. The shortest distance AP from a point A to a straight line OR is 12 cm, and Q. R are 15 cm and 20 cm distance from A on opposite sides of AP. Prove that QAR is a right angle.​

Answer 1

Step-by-step explanation:

We have AP = 12 cm, AQ = 15 cm and AR = 20 cm. Now, Δ APR is a right triangle as AP ⊥ QR and AP is the shortest distance from point A to line QR. ⇒ PQ = 9 cm.