Question

16. The solubility of potassium chlorate is given at different temperature
20°.
Temperature
40° 60° 80°. 100
8.5.
16.3.
Solubility (g/100g).
27.5. 42.5. 59.5​

Answer 1

Explanation:

Let volume of solution be V ml which contains 34.7gm of KCl and 100gm of water.

Density =(34.7+100)/V=1.3gm/ml

134.7=1.3V

V=134.7/1.3ml=103.61ml

w/V=mass of KCl in100mlof Sol

103.61ml of KCl contains 34.7g of KCl

100ml of KCl contains 103.61/34.7×100=33.49gm100ml.