Physics, asked by sudhirtomar824, 1 month ago

16. The value of acceleration due to gravity g
a Increases with height
b. Decreases with height
C. Remains same with height
d First increases then decreases​

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Answered by parth1902p
0

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Choose the correct alternative :(a) Acceleration due to gravity increases/decreases with increasing altitude.(b) Acceleration due to gravity increases/decreases ...

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(a) Acceleration decreases according to formula g' = g(1 - 2h/R) ,where h is height and R is radius of earth.(b) Acceleration decreases according to formula ... More

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Acceleration due to gravity - - - - - - - - - - with height from the surface of ... - Toppr

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Acceleration due to gravity - - - - - - - - - - with height from the surface of the earth.

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Choose the correct alternative :(a) Acceleration due to gravity increases/decreases with increasing altitude.(b) Acceleration due to gravity increases/decreases with increasing depth (assume the earth to be a sphere of uniform density).(c) Acceleration due to gravity is independent of mass of the earth/mass of the body.(d) The formula - G Mm(1/r2 - 1/r1) is more/less accurate than the formula mg(r2 - r1) for the difference of potential energy between two points r2 and r1 distance away from the center of the earth.

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(a) Acceleration decreases according to formula g' = g(1 - 2h/R) ,where h is height and R is radius of earth.(b) Acceleration decreases according to formula g' = g(1 - d/R) ,where d is depth and R is radius of earth.(c) Acceleration due to gravity is given by the formula: g = GMeRe^2 Hence, it is independent of mass of body, but is dependent on mass of earth.(d) Gravitational potential energy is given by the formula: U = - Gm1m2r g = GMeRe^2 assuming distance between object and earth is nearly equal to the radius of the earth.Substituting the second equation in first, we get U ≈ mgh Hence, the first formula is more accurate.

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As the altitude increases, the acceleration due

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