Question

16. The value of tan lº tan 2° tan 3º ... tan 89° is
(a) 0
146) 1
(d) 1 x 2 x...89
(c) 89
​

Answer 1

tan1.tan2.tan3..........tan89

=(tan1.tan89)(tan2.tan88)...........

=1.1.1...........

=1

hope this answer will make u happy....