Question

16) The velocity of a particle of mass - 150gram changes from
8ms to 12ms in 2 seconds assuming that a constant force
acts on it find magnitude of the force​

Answer 1

Given:-

→ Initial velocity of the particle = 8m/s

→ Final velocity of the particle = 12m/s

→ Mass of the particle = 150g

→ Time taken = 2s

To find:-

→ Magnitude of force

Solution:-

Firstly, let's convert the mass of the particle from g to kg.

=> 1g = 0.001kg

=> 150g = 150(0.001)

=> 0.15kg

By Newton's 2nd law of motion, we know that:-

=> F = m(v-u)/t

Where:-

• F is force

• m is mass of the particle

• v is final velocity of the particle

• u is initial velocity of the particle

• t is time taken

=> F = 0.15(12-8)/2

=> F = 0.15(4)/2

=> F = 0.15(2)

=> F = 0.3 N

Thus, the magnitude of force is 0.3 N.

Answer 2

Explanation:

Given:-

mass=m=150g=0.15kg

initial velocity =u =8m/s

Final velocity =v=12m/s

Time taken =t=2s

To find:-

magnitude of force

Solution:-

if

F=force

u=initial velocity

v=final velocity

t=time taken

m=mass

Then,

• According to Eizak Newton 's second law of motion

${:}\longrightarrow$${\boxed{F={\frac {m (v-u)}{t}}}}$

[by putting values]

${:}\longrightarrow$${\Huge {F={\frac {0.15 (12-8)}{2}}}}$

${:}\longrightarrow$${\Huge {F={\frac {0.15 ×{\cancel {4}}}{{\cancel{2}}}}}}$

${:}\longrightarrow$${\Huge {F= 0.15×2}}$

${:}\longrightarrow$${\Huge {{\underline{\boxed {\bf {0.3N}}}}}}$