Question

16) The work done by a body on application of a constant force is the product of the constant force and the distance travelled by the body in the direction of force. Express this in the form of a linear equation in two variables and draw its graph by taking the constant force as 3 units. What is the work done when the distance travelled is 2 units. Verify it by plotting the graph.

Answer 1

Your Answer:-

It is Given that

$\tt y= Fx \\\\ \tt Where,\\\\ \star y =Work\ \ Done \\\\ \tt \star F = force \\\\ \tt \star x=distance/displacement$

Also Given ,

force = 3 units

So, y = 3x

=> y - 3x = 0

So, this is the linear equation in two variables.

So, Now next part of the Question

We have Given that x=2units

y - 2(2) = 0

=> y = 6

So, work done is 6 units

Now verifying,

By plotting the graph

Let y =0

=> 0 = 3x

=> 0 = x

So, x = 0

So, the point is A(0,0)

And

Let x = 1

=> y = 3(1)

=> y = 3

So, the point is B(1,3)

To verify the answer,

draw a perpendicular to x axis at the point (2,0) meeting the line y - 3x = 0 at any point, So the coordinates of intersection is (2,6). This shows y = 6 , so work done is 6 units

Answer verified

Answer 2

it is correct answer dear