16. Three resistors are connected as shown in the diagram.
1022
C
A
5 22
B
1 amp.
mm
15 22
Through the resistor 5 ohm, a current of 1 ampere is flowing.
(i) What is the current through the other two resistors ?
(ii) What is the p.d. across AB and across AC?
(iii) What is the total resistance ?
1:
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Answer:
Q1. I=IR2/R1+R2
=1×15/10+15
=15/25=0.6A
I=IR2/R1+R2
=1×10/10+15
=10/25=0.4A
Q2. Pd across AB,
V=5V
Pd across AC,
V=AB+BC
=5V+6V(1/R=1/R1+1/R2)where R1 is 10 and R2 is 15.
=11V
Q3. Total resistance =5ohm+6ohm
=11 ohm
Hope it will helpful.
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