Question

16. Transform the equation x cosa + y sin a =p
= 1)
length of the intercepts cut off by it on the axes
in the form of
X у
+
a b
and find out the
length of the intercepts cut off by it on the axes.​

Answer 1

Answer:

. Transform the equation x cosa + y sin a =p

. Transform the equation x cosa + y sin a =p= 1)

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axes

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axesin the form of

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axesin the form ofX у

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axesin the form ofX у+

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axesin the form ofX у+a b

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axesin the form ofX у+a band find out the

. Transform the equation x cosa + y sin a =p= 1)length of the intercepts cut off by it on the axesin the form ofX у+a band find out thelength of the intercepts cut off by it on the axes