16. Two identical capacitors have the same capacitance
C. One of them is charged to potential V, and other
to V2. The negative end is joined with the positive
end of other capacitor. When the other two
remaining ends are connected the change in energy
of combined system is:-
(1) C/4(V1 - V2)²
(2) C/4(V1+ V2)²
(3) C/4(V1²+ V2²)
(4) C/4(V1²-V2²)
Answers
Answered by
3
Answer:
Pls check if it is correct or not
Attachments:
Similar questions