Physics, asked by sagarbaudh18, 6 months ago

16. Two identical capacitors have the same capacitance
C. One of them is charged to potential V, and other
to V2. The negative end is joined with the positive
end of other capacitor. When the other two
remaining ends are connected the change in energy
of combined system is:-
(1) C/4(V1 - V2)²
(2) C/4(V1+ V2)²
(3) C/4(V1²+ V2²)
(4) C/4(V1²-V2²)​

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Answers

Answered by Anonymous
17

Answer:

(3) C/4(V1²+ V2²)

Explanation:

hope it helps you ✌️

Answered by guri2110
1

Answer:

4 is the right one.....

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