Question

16. Two point charges 2 C and 3 uC are placed at two corners of an equilateral triangle of side 20 cm in free space. Calculate the magnitude of resultant electric field at the third corner of the triangle. Ir an a - particle is placed at the third corner, what is the force acting on it? (Charge on a - particle is 3.2 x 10-19 C).​

Answer 1

Answer:

Electricle field = (E−ECos60  

0

)  

x

^

+(ESin60  

0

)  

y

^

​

 

=  

2

E

​

 

x

^

+  

2

E  

3

​

 

​

 

y

^

​

 

=E(  

2

1

​

 

x

^

+  

2

3

​

 

​

 

y

^

​

)

=  

(20×10  

−2

)  

2

 

k(10  

−8

)

​

(  

2

1

​

 

x

^

+  

2

3

​

 

​

 

y

^

​

)

E=  

4×10  

−2

 

9×10  

9

×10  

−8

 

​

 

E=2250(  

2

1

​

 

x

^

+  

2

3

​

 

​

 

y

^

​

)

∣E∣=2250  

4

1

​

+  

4

3

​

 

​

 

∣E∣=2250 N/C

Answer 2

Explanation:

2250n/c is right answer for tis question