Question

16. Two spheres A and B of masses m, and m, respective collide. A is at rest initially and B is moving with velocity V - along x-axis. After collision B has a velocity 2 in a direction perpendicular to the original direction, The mass A moves after collision in the direction.​

Answer 1

Answer:

Explanation:

Here, mass of A=m1, mass of B=m2

Initial velocity of A,U1=0

Initial velocity of B,u2=υ,along x− axis. ltbr. After collision, let final velocity of A along x− axis be vx and final velocity A along y− axis be υy.

Final velocity of B=υ2 along Y− axis.

Applying principle of conservation of linear momentum along x− axis.

m1×0+m2υ=m1υx+m2×0

υx=m2υm1....(i)

Applying principle of conservation of linear momentum along Y−aξs,

m1×0+m2×0=m1υy+m2(υ2)

or υy=−m2υ2m1...(ii)

If mass A moves at angle θ with the X−axis, then

tanθ=υyυx=−m2υ2m1×m1m2υ=−12

∴θ=tan−1(12) to the x−axis