Question

16 upon root 41 - 5 rationalise the denominator

Answer 1

Hope this will help you.

Answer 2

$\frac{16}{ \sqrt{41} - 5} \\ \\ = \frac{16}{ \sqrt{41} - 5} \times \frac{ \sqrt{41} + 5}{\sqrt{41} + 5} \\ \\ = \frac{16 \times (\sqrt{41} + 5)}{(\sqrt{41} - 5)(\sqrt{41} + 5)} \\ \\ = \frac{16 \times (\sqrt{41} + 5)}{ {( \sqrt{41}) }^{2} - {5}^{2} } \\ \\ = \frac{16 \times (\sqrt{41} + 5)}{41 - 25} \\ \\ = \frac{\cancel{16} \times (\sqrt{41} + 5)}{\cancel{16}} \\ \\ = \sqrt{41} + 5$