Question

16. Velocity versus time graph of a ball of mass 100 g rolling on a concrete floor is shown below. Calculate the acceleration and the frictional force of the floor on the ball?

100

80

40+

20

ó

v m/s

2

4 4

6

8

10 10

(s)-​

Answer 1

Answer:

1000m/s

Explanation:

a=v-u/t

=80-0/8

=10

a=10

f=ma

=100*10

=1000

=1000m/s

hope you now clear

Answer 2

complete question:

Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown in Figure given below. Calculate the acceleration and frictional force of the floor on the ball.

Velocity:    0      20      40    80    100

Time     :    2        4        6        8     10

Answer:

The acceleration of the floor is $-10 ms^{-2}$ and the frictional force of the floor on the ball is 1N

Explanation:

Given: Mass of ball rolling on a concreter floor is 100g

To find: The acceleration and frictional force of the floor on the ball.

Solution:

Mass m = 100g

convert g into kg

M = $\frac{100}{1000}$

m = 0.1 kg

time t = 8s

We know that,

acceleration due to gravity,

a = $\frac{v-u}{t}$

V = final velocity  

v = 0

u = initial velocity  

u =  100m/s

a = $\frac{100 }{10}$

a = $-10 ms^{-2}$

There is only frictional force action on the body,

Therefore force,

F = ma

F = 0.1 × 10

F =  1 N

Final answer:

The acceleration of the floor is $-10 ms^{-2}$ and the frictional force of the floor on the ball is 1N

SPJ3