Question

16 What should be subtracted from a +b +c2-ab-bc-9 to get ab +bc +ca+abc+9?​

Answer 1

Answer:

Given a+b+c=9 & ab+bc+ca=26

As a

3 +b 3 +c 3

−3abc=(a+b+c)(a 2 +b 2 +c 2 −ab−bc−ca)

⇒(a 3 +b 3 +c 3 −abc)=(a+b+c)[(a+b+c) 2 −3(ab+bc+ca)]

⇒(a 3 +b 3 +c 3 −3abc)=9[81−78]=27

Step-by-step explanation:

i hope its help to you okkkkkk

Answer 2

Answer:

a+b+c2-2ab-2bc-ca-abc-18