Question

16- When 200 gms of ice at 0°C is mixed with 100 gms of water at 100°C, the final physical state of the
mixture after equilibirium has been established is:
(a) Solid state
(b) Liquid state (c) Gaseous state (d) None of these​

Answer 1

Explanation:

Correct option is

A

13.33

∘

C

Let the final temperature of the mixture be T.

Then 100×80+100(T−0)×1/2100×80+100(T−0)×1/2

(as specific heat of ice is 0.5cal/g/℃ and specific heat of water is 1cal/g∘C)

=100×1×(100−T)

Solving, we get T=13.33℃