16 women can do a piece of work in 10 days while 15 men can do the same work in 12 days. All men and all women work alternately starting with all men, then find the time taken by them to complete the whole work?
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Answer:
11 Days
Step-by-step explanation:
16 women can do a piece of work in 10 days
Work = 160 Women day = W
1 woman 1 day work = W/160
16 woman 1 day work = 16 * W/160 = W/10
15 men can do a piece of work in 12 days
Work = 180 men day = W
1 man 1 day work = W/180
15 men 1 day work = 15 * W/180 = W/12
Work done in 1st 2 days
W/10 + W/12
= (W/60)(6 + 5)
= 11W/60
Number of day required to complete work W = 2* W/(11W/60) > 10
Work completed in 10 Days = (10/2) * 11W/60 = 11W/12
Work remaining = W - 11W/12 = W/12
W/12 Work is done by 15 men in 1 day
so total day required = 10 + 1 = 11 Days
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