Question

16. Write down the relationship between zeroes and
co-cfficient of
quadratic polynomial
p(x)=ax? + bx+c. (a + 0). ifa and are the zeroes
of the polynomial p(x)​

Answer 1

Answer:

General form of quadratic polynomial is ax 2 + bx +c where a ≠ 0. There are two zeroes of quadratic polynomial. Product of zeroes =ca c a = Constant term Coefficient of x2 Constant term Coefficient of x 2 .

Step-by-step explanation:

please follow

Answer 2

Answer:

We get the relation : \alpha +\beta =\dfrac{-b}{a}\ and\ \alpha \beta =\dfrac{c}{a}α+β=

a

−b

and αβ=

a

c

Step-by-step explanation:

Since we have given that

Quadratic polynomial is

ax^2+bx+cax

2

+bx+c

So, relationship between the zeroes and coefficients of the quadratic equation is given by

\begin{gathered}\alpha +\beta =\dfrac{-b}{a}\\\\\alpha \beta =\dfrac{c}{a}\end{gathered}

α+β=

a

−b

αβ=

a

c

Hence, we get the relation : \alpha +\beta =\dfrac{-b}{a}\ and\ \alpha \beta =\dfrac{c}{a}α+β=

a

−b

and αβ=

a

c

# learn more:

Find a quadratic polynomial whose zeroes are reciprocal of the zeroes of the polynomial ax^2+bx+c

https://brainly.in/question/3683850