Question

16. Write the value of x for which 2x, x + 10 and 3x + 2 are in AP,​

Answer 1

Answer:

formula - if a ,b,c are in AP

then → 2b = a +c

so,

2( x +10) = 2x + 3x + 2

=> 2x + 20 = 5x +2

=> 20 -2 = 5x - 2x

=> 18 = 3x

=> x = 18/3 = 6

so, the value of x is 6

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Answer 2

Answer:

Mark it as brainlist

Step-by-step explanation:

Since 2x,x+10 and 3x+2 are in AP

Therefore the common difference must be same.

So x+10-2x=3x+2-(x+10)

-x+10=3x+2-x-10

-x+10=2x-8

-x+10-2x+8=0

-3x+18=0

-3x=-18

x=−18−3

x=6