(16^x ) (256)= 4^6,then find 40(9^x+ 9^-x)/9^x- 9^-x
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1
Answer:
Correct option is
A
ln2−ln3
ln(
3
−1)+ln2
6
x
+4
x
=9
x
divide by 4
x
to form (
2
3
)
x
4
x
6
x
+1=
4
x
9
x
(
2
3
)
x
+1=(
2
3
)
2x
((
2
3
)
x
)
2
−(
2
3
)
x
−1=0
So (
2
3
)
x
=
2
1±
1−4.1(−1)
=
2
1±,
5
For positive solution
(
2
3
)
x
=
2
1+
5
Applying logarithm
xln(
2
3
)=ln(
2
1+
5
)
ln
b
a
=lna−lnb
x=
ln3−ln2
ln(1+
5
)−ln2
.
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