(16 x cube - 8 x square 4 ) ÷ 4x
Answers
Answered by
1
Answer:
28x^3 + 16x^2 + 8x + 6 = 2(8x^2 + 4 + y)
2(14x^3 + 8x^2 + 4x + 3)= 2(8x^2 + 4 + y)
14x^3 + 8x^2 + 4x + 3 = 8x^2 + 4 + y
14x^3 + 8x^2 -8x^2 + 4x + 3-4 = y
14x^3 + 4x -1 = y
Similar questions