16 X square + 4 x minus 2
Answers
Step-by-step explanation:
16x2 + 4x - 2 =0.
2 • (8x2 + 2x - 1) =0.
8x^2 + 2x - 1= 0/2.
8x^2 + 2x - 1 = 0.
Factoring 8x2 + 2x - 1
The first term is, 8x2 its coefficient is 8 .
The middle term is, +2x its coefficient is 2 .
The last term, "the constant", is -1
Step-1 : Multiply the coefficient of the first term by the constant 8 • -1 = -8
Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is 2 .
-2 + 4 = 2 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 4
8x2 - 2x + 4x - 1
Step-4 : Add up the first 2 terms, pulling out like factors :
2x • (4x-1)
Add up the last 2 terms, pulling out common factors :
1 • (4x-1)
Step-5 : Add up the four terms of step 4 :
(2x+1) • (4x-1)
Which is the desired factorization
2x+1 =0 (or) 4x-1 =0.
2x=-1 (or) 4x = 1
x= -1/2 (or) x= 1/4.