Question

16 x to the power 5 minus 144 x to the power 3. Factorise it using identies.

Answer 1

Solution :

16x^5 - 144x³

= 16x³ × x² - 16 × 25x³

= 16x³ ( x² - 25 )

= 16x³ [ x² - 5² ]

[ By algebraic identity ,

a² - b² = ( a + b )( a - b ) ]

= 16x³ ( x + 5 )( x - 5 )

••••

Answer 2

Answer:

$16x^5-144x^3=16x^3(x-3)(x+3)$

Step-by-step explanation:

Given Expression, $16x^5-144x^3$

We have to factorize the given expression

Consider,

$16x^5-144x^3$

Take 16x³ common from both term

⇒ 16x³ ( x² - 9 )

⇒ 16x³ ( x² - 3² )

using idenity a² - b² = ( a - b ) ( a + b )

⇒ 16x³ ( x - 3 ) ( x + 3 )

Therefore, $16x^5-144x^3=16x^3(x-3)(x+3)$