Question

16(x+y)^2+24(x+y)(y-z)+9(y-z)^2

Answer 1

Given -

16 ( x + y )² + 24 ( x + y ) ( y - z ) + 9 ( y - z )²

{ Using identity -

( a + b )² = a² + b² + 2ab }

Here, a = 4 ( x + y ) and b = 3 ( y - z )

= [ 4 ( x + y ) ]² + ( 2 ) [ 4 ( x + y ) ] [ 3 ( y - z ) ] + [ 3 ( y - z ) ]²

= [ 4 ( x + y ) + 3 ( y - z ) ]²

^^"

Answer 2

16 ( x² + y² + 2xy ) + 24 ( xy - xz + y² - yz) + 9 ( y²
+ z² - 2yz

=> 16 x² + 16 y² + 32 xy + 24 xy - 24xz + 24 y² - 24yz + 9 y² + 9 z² - 18 yz

=> 16 x² + 49 y² + 56 xy - 24 xz + 6 yz + 9 z²

=> 16 x² + 49 y² + 9 z² + 56 xy + 6yz - 24 xz