Question

16. xy(z2 + 1) + z(x2 + y2) can be factorised as
(a) (xy + z) (yz + x) (b) (zx + y) (xy + z)
(c) (yz + x) (zx + y) (d) (x2 + y2) (z + x)​

Answer 1

Answer:

C

Step-by-step explanation:

$xy( {z}^{2} + 1) + z( {x}^{2} + {y}^{2} )$

$xy {z}^{2} + xy + {x}^{2} z + {y}^{2} z$

$xy {z}^{2} + {y}^{2} z + xy + {x}^{2} z$

$yz(xz + y) + x(y + xz)$

$(yz + x)(zx + y)$

Option C