Math, asked by youshenee1388, 1 year ago

16 years ago, my uncle was 8 times older than me. After 8 years from today, my uncle will be thrice as old as i will be at that time. Eight years ago, what was the ratio of my age and my uncle‘s age?

Answers

Answered by anurag7315
2

Step-by-step explanation:

let your present age x yrs

your uncles present age is y yrs

16 yrs ago your age was= x-16

your uncle's age was = y-16

ATQ 8×(x-16)=y-16

8x -128 -y +16=0

8x -y = 112 ........(i)

8 yrs from today your age will be = x+8 yrs

and your uncle's age will be = y+8 yrs

ATQ

3×(x+8)=y+8

3x +24 -y -8=0

3x-y=-16 .........(ii)

now subtract eq (ii) from eq (i)

we get

8x - y = 112

3x - y = -16

- + +

____________

5x = 128

x = 25.6 yrs

put in eq (ii)

3(25.6) -y = -16

y = 76.8 + 16

y = 92.8 yrs

Now 8 yrs ago your age was 25.6 - 8 = 17.6 yrs

your uncle's age was 92.8-8=86.8 yrs

now their ratio is

(17.6)/(86.8)

= 44:217

Answered by Anonymous
7

Answer:

ans =  > 11 \ratio53 \\

Step-by-step explanation:

=  >  present \: age \: of \: your \: uncle = x \\  \\  =  > your \: present \: age = y \\  \\  =  > \: 16 \: years \: ago \: your \: uncle \: age = x - 16 \\  \\  =  > 16 \: years \: ago \: your \: age = y - 16 \\  \\  =  > 16 \: years \: ago \: uncle \: age \: was \: 8 \: times \\  \:  \: \:  \:  \:  \:  \:  \:  \:  times \: older \: than \: you \\  \\  \therefore \: x - 16 = 8(y - 16) \\  \\  \therefore \: x - 16 = 8y - 128 \\  \\  \therefore \: x - 8y =  - 128 + 16 \\  \\  \therefore \: x - 8y =  - 112.....equation(1) \\  \\  =  > 8 \: year \: after \: your \: uncle \: age = x + 8 \\  \\  =  > 8 \: years \: after \: your \: age = y + 8 \\  \\  =  >  after \: your \: uncle \: age \: will \: be \: 3 \: times  \\  \:  \:  \:  \:  \:  \:  \: \: older \: than \: you \\  \\  \therefore \: x + 8 = 3(y + 8) \\  \\  \therefore  \: x + 8 = 3y + 24 \\  \\  \therefore \:  x - 3y = 24 - 8 \\  \\  \therefore \: x - 3y = 16....equation(2) \\  \\  =  > solve \: to \: equation(1) \: and \: equation(2) \\  \\ x - 8y =  - 112 \\ \\ x - 3y =  \:  \:  \: 16 \\  -  \:  \:  \:  +  \:  \:  \:  \:  \:   \:  \: -  \\ ....................... \\  \:  0 \:  - 5y =  - 128 \\  \\  \therefore \: y =  \frac{128}{5}  = 25.6 \: year \\  \\  =  > put \:  value \: of \: y \: in \: equation(2) \\  \\  x - 3(25.6) = 16 \\  \\ x - 76.8 = 16 \\  \\ x = 92.8 \: year  \\  \\  =  > now \: find \: to \: ratio \: 8 \: years \: ago \:  \\ \: \:  \:  \:  \:  \:  \: \: your \: age \: and \: your \: uncle \: age \\  \\  =  >  \frac{25.6 - 8}{92.8 - 8}  \\  \\  =  >  \frac{17.6}{84.8}  \\  \\  =  >  \frac{176}{848}  \\  \\  =  >   \frac{11 \times 16}{53 \times 16}  \\  \\   =  >  \frac{11}{53}  \\  \\ your \: ans = > 11 \ratio53

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