ʜᴏᴡ ᴍᴀɴʏ ᴍᴏʟᴇꜱ ᴏꜰ ɴᴀᴏʜ ᴀʀᴇ ᴘʀᴇꜱᴇɴᴛ ɪɴ 160ɢ ᴏꜰ ɪᴛ
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Given:-
→Mass of NaOH(Sodium Hydroxide) = 160g
To find:-
→Number of moles present in 160g of NaOH
Solution:-
•Atomic mass of Na(Sodium) = 23u
•Atomic mass of O(Oxygen) = 16u
•Atomic mass of H(Hydrogen) = 1u
Thus,molecular mass of NaOH:-
= 23+16+1
= 40u
Since,molecular mass of NaOH is 40u
Thus,molar mass of NaOH is 40g.
Now:-
Number of moles:-
Given mass/Molar mass
= 160/40
= 4 moles
Thus, 4 moles of NaOH are present
in 160g of it.
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