160g of aqueous solution of urea contains 40% urea by weight. Calculate the molality and mole fraction.
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40% by mass urea solution means 40 gram urea in 100 gram solution.
Thus molality can be given as,
m=(mass of urea in grams/molar mass of urea in gram per mole)*(1000/mass of solvent in grams)
Here mass of solvent can be given as,
Mass of solvent=Mass of solution - mass of solute
=100 - 40
=60
m=(40/60)*(1000/60)
m=200/18
m=11.11 molal
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