Question

161. A and B start from a given point and travel on a straight road at an average speed of 30 km and 50 km per hour respectively. A starts at 8 AM and B starts 3 hours later. Find the time when B meets A L073.30 pm (2) 3.20 pm (3) 4.30 pm (4) 4.20 pm​

Answer 1

Explanation:

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Answer 2

Answer:

Two bodies A and B start to travel from the same point on a straight road at an average speed of  $30Km/h$ and $50Km/h$  respectively. A starts at $8am$ and B starts $3$ hours later. The time when B meets A is $3.30 PM$

Explanation:

The average speed of A is $V_A=30km/h$

The average speed of B is $V_B=50km/h$

A starts at $8AM$ and B starts at $11AM$ ($3$ hours later)

Let's assume that after $11AM$ B has taken $x$  hours to catch A

Distance traveled by  B when it intercepts A is $d=V\times t=50\times x km$

at the time the distance traveled by A is $d=30\times 3+30\times x$

the distance traveled by A and B will be the same at the point of meeting

⇒

$\begin{array}{l}50x=90+30x\\20x=90\\x=4.5hrs\end{array}\begin{array}{l}\\\\\end{array}$

After $4.30 hrs$ they will meet so the time of the meeting will be $11+4.30=3.30 PM$