16²+12a greatest common monomial factor
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Answered by
12
Answer:
2,3,4and 6 is correct sum
Answered by
11
/* There is a mistake in the question. It must be like this */
/* We have,
16a² = 2×2×2×2×a×a ,
12a = 2×2×3×a
Common factor = 2×2×a = 4a
Therefore.,
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