Question

16²+12a greatest common monomial factor

Answer 1

Answer:

2,3,4and 6 is correct sum

Answer 2

/* There is a mistake in the question. It must be like this */

$Given \: Algebraic\: expression: 16a^{2} + 12a$

/* We have,

16a² = 2×2×2×2×a×a ,

12a = 2×2×3×a

Common factor = 2×2×a = 4a

$16a^{2} + 12a \\= (4a) \times 4a + (4a) \times 3\\= 4a( 4a + 3 )$

Therefore.,

$\red{ Greatest \: common \: monomial \:factor}\\\green { = 4a }$

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