Question

1672 cal of heat is given to one mole
of oxygen at 0°C keeping the volume
constant. Rise in temperature is
(cp = 6.4cal/gm/°K and R = 2cal/mole/°K)
(A) 33.6°C
(B) 36.3°C
(C) 63.3°C
(D) 8.24°C​

Answer 1

Answer:

33.6∘C

36.3∘C

63.3∘C

334.4∘C

Answer :

D

Solution :

ΔQV=nCVΔT

Explanation:

Answer 2

Answer:

Answer : D

Explanation: dQ= n.Cv.dT and Cp-Cv= R