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50gm of copper is heated to increase its
temperature by 10'C. If the same quantity of
heat is given to 10 gm of water, the rise in its
temperature is
(s. - 420J/kg !"C and S. -4200/kg/°C)
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Heat given to copper = (0.050×450×10)J
Now, let △T be rise in temperature of water
⇒0.050×420×10=0.010×4200×△T
⇒△T=5
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