Question

16a^2 - b^2 + 4b - 4 factorisation ​

Answer 1

Step-by-step explanation:

$16 {a}^{2} - {b}^{2} + 4b - 4$

${(4a)}^{2} - {b}^{2} + 4(b - 1)$

$(4a + b)(4a - b) + 4(b - 1)$

Now it can't be factorise further.

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