Question

16a^2b^2-25c^2b^2 factorize ​

Answer 1

The factors of $16a^{2}b^{2}-25c^{2}b^{2}$ are $(4ab+5cb)(4ab-5cb)$.

Step-by-step explanation:

The expression is:

$16a^{2}b^{2}-25c^{2}b^{2}$

The expansion of is:

$(a + b)(a - b) = a^{2}-b^{2}$

Use the above property to determine the factors of $16a^{2}b^{2}-25c^{2}b^{2}$ as follows:

$16a^{2}b^{2}-25c^{2}b^{2}=(4ab)^{2}-(5cb)^{2}$

                        $=(4ab+5cb)(4ab-5cb)$

Thus, the factors of $16a^{2}b^{2}-25c^{2}b^{2}$ are $(4ab+5cb)(4ab-5cb)$.