Question

16a cube -128 upon b cube

Answer 1

$(16 {a})^{3} - ( \frac{128}{b} {)}^{3} \\ =4096 {a}^{3} - \frac{2097152}{ {b}^{3} }$
so here is you r ans

Answer 2

Answer:

16a^3-128/b^3

Step-by-step explanation:

16. ( a^3 - 8. / b^3. )

16. [. a^3. -. 8. /. b^3. )

16. (. a -. 2 /. b. ). (. a^2 + 2a /b. +. 4. / b^2. )