Question

16à²+4b²+9c²-16àb+12bc-24​

Answer 1

Answer:

9a2+4b2+16c2+2ab−16bc−24ca

= (3a)2+(2b)2+(−4c)2+2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a)

Suitable identities is (x+y+z)3=x3+y3+z3+2xy+2yz+2xz

Therefore, (3a)2+(2b)2+(−4c)2+2(3a)(2b)+2(2b)(−4c)+2(−4c)(2a)

= (3a+2b−4c)2

Answer 2

Answer:

2(3a+2b-4c)

Step-by-step explanation:

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