Question

16a3-128 by b3 factorise

Answer 1

Answer:

16(a-2)(a²+2a+4)/b³

Step-by-step explanation:

We have to factorise  the following algebric expression

(16a³-128)/ b³.....(1)

Factorisation is the mathematical process of getting an expression in terms of multiplication of few terms which are called factors of the mother expression.

Now, to factorise the above term, we first take common 16 and 1/b³ from the actual expression (1).

The process is given below:

(16a³-128)/ b³

=(1/b³)×(16a³-128)

Now take 16 as common:

= (16/b³)×(a³-8)

= (16/b³)×(a³-2³)

= (16/b³)×(a-2)×(a²+2a+2²)

= (16/b³)×(a-2)×(a²+2a+4)

This is the solution.

Note: Formula of

a³-b³= (a-b) (a²+ab+b²)