Question

16a⁴-72a²b²+81b²
please solve​

Answer 1

Answer:

the answer is

16a4-72a2b2+81b2

Step-by-step explanation:

because no variables are in equal amount

Answer 2

$(a-b)^2 = (a^2-2ab+b^2)\\\\16a^4-72a^2b^2+81b^2 = (2a^2)^2 - 2*(2a)^2 * (3b)^2 + (3b^2)^2=(4a^2-9b^2)^2 \\\\\bf\underline{Answer} : (4a^2-9b^2)^2$

$\textrm{Hope \ it \ helps \ !!}$