Math, asked by dhruvshirali1, 1 year ago

(-16ab²c) ÷ (6abc)

gggggggggggggggggggggggggggggggggggggggggggggggggg ( BTW I WORTE THE 'g's' because the characters were too little. Ignore them. Thnx!!!

Answers

Answered by Anonymous
38

Answer:

Step-by-step explanation:

-16absquarec/6abc given

-16axbxbxc/6axbxc

-8b/3

Here we go

Answered by Anonymous
2


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\huge{\mathfrak{Solution}}

( - 16 {a}^{2} bc) \div (6abc)

 = > -16 {a}^{2} bc \times \frac{1}{ 6abc}

 = > \frac{ - 8a}{3}

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\huge{\mathfrak{Thanks♡♡}}
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