Math, asked by jyoti2462, 6 months ago

(16c^2- 4a^2 - 12ab-9b^2) by (2a+3b + 4c)​

Answers

Answered by adityavardhan630
2

Answer:

65

Step-by-step explanation:

get to see how the resulting never been able is it the more you can get to see how the resulting never been to be

Answered by IND21
3

Answer:

65 will be the answer

Step-by-step explanation:

Given:

4a

2

+9b

2

+16c

2

+12ab−24bc−16ac

Use the formula:

(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca

Simplify the equation.

4a

2

+9b

2

+16c

2

+12ab−24bc−16ac=(2a)

2

+(3b)

2

+(−4c)

2

+2×2×3ab+2×(−4)×3bc+2×(−4)×2ac

=(2a+3b−4c)

2

Thus, the factor of the equation is (2a+3b−4c)

2

.

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