16cot=12 find sinA +cosA
÷sinA-cosA
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16cot=12
Cot=12/16 =3/4 = B/P
B=3x
P=4x
By Pythagoras thm. We can find H.
H²=B²+P²
H²=(3x)²+(4x)²
H²=9x²+16x²
H²=25x²
H=5x
SinA=P/H = 4x/5x = 4/5
CosA=B/H= 3x/5x = 3/5
Now, SinA+Cos÷SinA-CosA
4/5+3/5÷4/5-3/5
4+3/5÷4-3/5
7/5÷1/5
7/5*5/1
=7 Ans..
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