Question

16g of H2 reacts with 50g of O, to yield H:0. Using this information answer the
following:
(a) Which one is the limiting reagent?
6) Calculate the maximum amount of H:O that will be formed.
(c) Calculate the amount of the excess reactant which remains unreacted.

Answer 1

Answer:

The balanced chemical equation is :

2H22×2=4g+O232g→2H2O2×18=36g

Step I. Determination of limiting reactant

4 g of H2 react with O2=32 g

∴ 3 g of H2 react with O2=324×3g=24g

But the amount of oxygen actually available = 29 g

As oxygen is available in excess therefore, hydrogen is the limiting reactant.

Step II. Calculation of the amount of water that can be formed

4 g of H2 in the reaction = 36 g

∴ 3 g of H2 require O2 for reaction =324×3g=24g

But oxygen which is actually present = 29 g

∴ Amount of oxygen left unreacted =29−24=5g.