Question

16g of oxygen and 3g of hydrogen are mixed and kept at 760mm pressure and 0°c. The total volume occupied by the mixture will be nearly?

Answer 1

Explanation:

760 mm of Hg = 1.013*10^5 N/m^2

0℃ = 273 °k

16 g for oxygen = 0.016 kg

gas const. of O2 = 259.85 J/Kg°k

gas const. of H2 = 4157 J/Kg°k

3 g of hydrogen = 0.003 kg

for oxygen volume occupied is given by

Vo = (0.016*259.85*273)/(1.013*10^5)

Vo = 0.0112 m^3

for hydrogen volume occupied is given by

Vh = (0.003*4157*273)/(1.013*10^5)

Vh = 0.0336 m^3

total volume occupied will be

=0.0112 + 0.0336 = 0.04481 m^3